A 22cm diameter bowling ball has a terminal speed of 85m/s. What is the ball's mass?

Answer 1

Vt=sqrt((2 m g)/p A Cd)
where
Vt is the terminal velocity,
m is the mass of the falling object, (in kg)
g is gravitational acceleration (9.81 m/sec^2),
Cd is the drag coefficient (it depends on the shape and speed we can use 0.5 in this case)
p is the density of the fluid the object is falling through, and
A is the object's cross-sectional area.

m=(Vt^2 p A Cd/2 g)

I hope it helps