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You are to design a procedure to determine experimentally the specific heat of an unknown liquid. You may not damage or destroy any equipment you use, and your method must be feasible and practical.

(a.) List the equipment you would need. Include a labeled diagram.

(b.) Describe the measurements you would make. Assign each measurement a symbol (such as time = t).

(c.) Show explicitly using equations how the measured quantities would be used to determine the specific heat of the unknow liquid.

(d.) Indicate one possible source of experimental error and discuss how it would affect your value for the specific heat. Justify your answer.

2007-02-07 12:45:19 · 2 answers · asked by Scratch22 1 in Science & Mathematics Physics

2 answers

1. Insulated container capable of holding liquid with lid and an with an agitator (a wire loop will do)
2. High heat conduction thin-walled container small enough so it does not touch (touches minimally) the walls of the insulated container with an agitator (a wire loop will do). The size of this container should be between 1/3 to ½ if the internal volume of the insulating container.
3. 2 thermometers

Place a known amount of test liquid into a test container. Place ice and water into the insulating container. When ice water reaches 0 deg C remove the ice and measure the mass of water. Measure and record the temperature of the test liquid and then place the container with test liquid into the bath. Agitate both water and test liquid periodically. Record the temperature when temperature of the test liquid equal to the temperature of the water.

Since q=m Cp(T2-T1) and q1=q2
We have
m(H2O)Cp(H2O) (T2-T1) = m(test) Cp(test liquid) (t2-t1)

Cp(test liquid)=[ m(H2O)Cp(H2O) (T2-T1)]/ m(test) (t2-t1)

The rest is up to you.

2007-02-08 04:51:19 · answer #1 · answered by Edward 7 · 0 0

do not use the microwave to warmth a toddler's bottle, except you purely warmth the water first and then upload the milk. yet i'd propose making the bottle and warming it with a bottle hotter. i imagine you will get one at Wal-Mart for like $20.00. or you should attempt searching on the information superhighway for one.

2016-11-26 01:13:41 · answer #2 · answered by ? 4 · 0 0

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