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has the same slope as 3x - y + 4 = 0 and contains the point (2, -3)

How do you turn a problem like the one above into slope-intercept form?

2007-02-07 12:39:15 · 2 answers · asked by jestinghoax 1 in Education & Reference Homework Help

2 answers

Step 1: Change the given equation to slope intercept form:
3x - y + 4 = 0

Add y to both sides:
3x - y + 4 + y = y
3x + 4 = y (slope-intercept form)

Step 2: Taking the slope intercept form equation, use the slope and the given point to define a new equation.
Slope = 3
Point = 2, -3
Slope = rise/run

Since for slope intercept you need to find the y-intercept (x = 0), take the negative value of x from your point (-2), and plug it as the run in your slope equation:
slope = rise / run
rise = slope * run = 3 * -2 = -6.

Thus, from point (2,-3), you run -2 and rise -6, giving you a y-intercept point of (0,-9).

Step 3: Given the slope and the y-intercept, write the new equation in slope intercept form:
y = = 3x - 9 (solution!)

2007-02-08 03:55:59 · answer #1 · answered by ³√carthagebrujah 6 · 0 0

So I'm guessing it's going to be something like y=3x + __

You're going to want to graph that line on paper, and think, "okay, so it intercepts with the other at 2,-3, so find that point and create the other line with the slope. Then you can find the y-intercept to complete the formula.

I'm just guesing however. I've never been asked to do questions like this. Anyone correct me if I'm totally wrong.

2007-02-07 20:46:02 · answer #2 · answered by meikai_derushie 3 · 0 0

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