3.0 x 10^4 J of heat energy is transferred to a 100 kg block of Al initially at 10 degrees Celsius?

Question

What will its final temperature be? I need the formula I am unsure how to do this problem?

Answer 1

What you need to know is the specific heat of Aluminum.
Here is a link with the formula:
http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/spht.html#c1
which states that Q=cm*delta-T
So, delta-T = Q/cm
where Q = heat added,
c = specific heat, and m = mass
Aluminum has a specific heat of .9 J/gm K at 20 degrees C, which is the closest I could find.
so delta-T = 3x10^4 J/[(.9J/gm K)*100^10^3 gm)
= 3*10^4/.9/100/10^3 K
= .3/.9 K
or about 1/3 of a degree C

Answer 2

If heat is transferred to or from a body its temperature will change. The change will be given by the following formula:

Amount of Heat = mass (specific heat) (final temp - initial temp)

The specific heat is different for different sunbstances. Consult a table of specific heats to obtain a value for aluminum. If the heat comes out + it meas that heat is added to the body, if - it means heat is rejected by the body. The sign depends on the initial and final temp.