Average Speed,Velocity, acceleration Pls help?

Question

1. A car undergoes a displacement of 500m due east, followed by another displacement due south of 1200m.
a) Calculate the total distance traversed by the car.
b) Calculate the total displacement of the car.

2. If the car in problem 1 traveled at 36.0km/h during the first part of the trip and at 90.0km/h during the remainder,
a) Calculate the average speed for each part of the trip
b) Calculate the average velocity for each part of the trip
c) Calculate the time for each part of the trip
d) Calculate the average speed for the whole trip
e) Calculate the average velocity for the whole trip
f) Calculate the instantaneous speed of the car as it passes the 1km point of the trip
g) Calculate the average velocity of the car as it passes the 1km point of the trip

Answer 1

1. a) it sis St=S1+S2=500+1200=1700m
b)Since you are dealing with vectors orthogonal components
we have
magnitude |D|= sqrt([v(east)]^2+[v(south)]^2)
D=1300m SE
angle=arcTan(1200/500)=67.4

2. Use information above
a)V(avg)=|D|/t
t= D1/V1+D2/V2
and so on

Answer 2

You have a disagreement on final answer. I agree with those that said 3.22 m/s^2. Especially the formula used by DavidK93 and some others. chaospersoni...'s mistake is at the step "to solve for t, t=d/v". The velocity is increasing as the plane goes down the runway. For v, the average velocity is needed, 35m/s is the final velocity. The average velocity would be 1/2 of the final. chaospersoni...'s result is therefore double.