i need help with teh Archimedes Principle about buoyancy!!?

Question

ok we had to create cardboard boats for my science class, and now we have to write a summary and part of it says:

Archimedes Principle states that "The buoyant force on a body immersed in a fluid is equal to the weight of the fluid displaced by that object." An object floats when its weight is equal to the buoyant force. Describe how this principle applies to the flotation of your boat,

Descrube how you would calculate the buayant force exerted on your boat by the water. What measurements would you take and how would you interpret them?

ok i just put exactly what the paper said, so if anyone can help me please!!!

Answer 1

The buoyant force exerted on the boat is equal to the weight of the boat. And so the weight of water displaced is equal to the weight of the boat. You don't have to calculate, merely weigh the boat. If you want to go into more detail you can mark the waterline where the boat floats. Using the weight of the boat and the density of water you can calculate the submerged volume of the boat (below the waterline). It's simply the volume of water equal to the weight of the boat.

Answer 2

Calculate the bouyant force by first weighing the boat before you put it in the water. this is the empty weight, and equals the bouyant force of the empty boat.

Then drop coins into the boat until it sinks. Retrieve the coins, dry them and weigh them. Or if you know how much each coin weighs, you can just count the weight as you drop them in. The weight of the coins will be the useful load.

Add the useful load to the empty weight, and that is the gross weight or total displacement. Total displacement = total bouyant force.

Answer 3

It takes 12 seconds for the Y.A. questions to load for me to be able to click on the [add your answer] box. does this mean my computer is slow??