URGENT! wheatstone bridge experiment?

Question

i set up a Wheatstone bridge with a standard resistor, and a galvanometer. i put a 15cm long wire in the setup and varied the galvanometer to a point where it did not deflect. i did this for varied lengths of the wire, l, and recorded the lengths of no deflection. then i found their mean lx.

i then interchanged the resistor and the wire and repeated the process. again i found the mean of varied galvanometer lengths, ly. then i found the ratio lr = lx/ly

i then plotted l vs lr.

how do i find the resistivity of the wire?

i know the wire's cross sectional area.

Answer 1

The resistivity is found by multiplying the R constant(which you found with your wheatstone bridge and galvanometer) by A over l. Resistivity = R(cross-sectional area divided by length). Resistivity = R(A/l)

Answer 2

R = resistivity x(length/cross section)

so resistivity = (cross section/length) X resistance