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When a substrate that is catalyzed by an enzyme is present in high concentrations, the effect on the rate of a reaction by changeing the substrate concentration can be described using zeroth-order kinetics. If the concentration of a such a substrate is changed from 2.49 × 10−3 M to 4.53 × 10−1 M, by what factor does the rate of the reaction change ?


That is rate (4.53e-1M) = f × rate (2.49e-3M)

what is the vaule of f ?

2007-02-07 05:31:39 · 2 answers · asked by checa1215 2 in Science & Mathematics Chemistry

2 answers

in a zero order reaction the rates stay the same so f is just equal to 1

2007-02-07 07:25:06 · answer #1 · answered by Marty Kay 2 · 0 0

1

2007-02-09 00:53:22 · answer #2 · answered by Raki 3 · 0 0

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