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If we put a conductor between two oppositely charged particles, what will equipotential lines look like?

2007-02-07 04:52:56 · 4 answers · asked by Anonymous in Science & Mathematics Physics

4 answers

Because the electric potential in a conductor would be uniform, it will itself be one of the equipotential lines. The rest of the equipotential lines would be a series of ovals around each of the charged particles, even though on a chart of limited size, many of them will go off the page.

This assumes that the conductor is not connecting the points where the charged particles are, because then that is a different problem, and no longer a static one.

2007-02-07 04:58:32 · answer #1 · answered by Scythian1950 7 · 0 0

that is an attractive question. My wager is you're acceptable; the ring may act as a Faraday cage, yet i do not comprehend how the ring may distort what may in the different case be parallel equipotential and container strains. it should be uncomplicated to make sure experimentally. In 2d three hundred and sixty 5 days physics we were given a shallow tray of copper sulphate answer and a voltmeter and we mapped the equipotential strains for electrodes in diverse configurations. for sure, the container strains are at acceptable angles to the equipotential strains.

2016-11-25 23:49:52 · answer #2 · answered by ? 4 · 0 0

Check out the link below. it may give you some explanation.

2007-02-07 05:04:20 · answer #3 · answered by Anonymous · 0 0

one directional flowing twards the neg

2007-02-07 04:55:22 · answer #4 · answered by Robert P 6 · 0 0

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