math question. what is the age?

Question

erin's age is 3 times warren's. in 4yrs she will be twice as old as he will be. how old is each now? can you help me set up the equation?

Answer 1

E is Erin's age now, E+4 is her age in 4 years. W is Warren's age now, W+4 his age in 4 years. You're told:

E = 3W
E+4 = 2(W+4) ......... so replacing E with 3W,

3W + 4 = 2W + 8
W = 4
E = 12

Answer 2

Warren is 4, Erin is 12. In 4 years, Warren will be 8 and Erin will be 16.

Answer 3

Ofcourse I will love here the sololution goes
Let the age of erin be E and the age of Warren be W
Since the age of erin is three times so you have to multiply the age of warren by 3 to make equal to both of the ages
So accordinng to the problem
E=3W
Now again according to the problem
After 4 Years the age of Erin= E+4
And the age of warren=W+4
Now since erin is doble that of the age of warren so you have to multilply the age of warren to make both of the age equal
Hence
E+4=2(W+4)
E+4=2W+8
Now subsitute the value of "E" from first equation
3W+4=2W+8
3W-2W=8-4
W=4
So the age of erin =4*3
=12
I hope this helps

Answer 4

2 equations

e=3*w
e+4=2*(w+4)

sub equation 1 into 2,

3w + 4 = 2*w+8 ==> w=4 yrs old

sub back into equation 1,

e = 12 yrs old

in 4 yrs warren will be 8 and erin will be 16.

Answer 5

x is Erin's age now and y is Warren's age now.
At the moment, x=3y .....(1)
in 4 years time, x+4=2(y+4)
=>3y+4=2y+8
=>y=4 & x=12
So at the moment, Erin is 12 and Warren is 4

Answer 6

e = 3w
e+4 = 2(w+4)

Have fun!