2007-02-07 04:25:58 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
depends on the bomb and where it explodes.
I think a good rule of thumb is 1 mile radius from ground zero is annihilated. Between 1 mile and 10 mile radius is a radiation sickness kill zone and beyond that increased risk of cancer and whatnot.
2007-02-07 04:29:11 · answer #1 · answered by Dr W 7 · 1⤊ 0⤋
It depends on the yield and the height of the explosion.
For every yield there is an optimum height to maximize damage.
The "area" also depends on your idea of what's destroyed: what's completely vaporized or what's just damaged beyond repair, etc. etc.
Most ballistic warheads are in the 500 kiloTon to 1 MegaTon range. Exploded at optimum height, a 1 MegaTon warhead will produce 160+ mph wind (due to 5-10 psi overpressure) at a radius of 14,000 feet from "ground zero", and 75+ mph winds at approx. 30,000 feet from GZ.
2007-02-07 12:55:46 · answer #2 · answered by tlbs101 7 · 2⤊ 0⤋
it depends on the yield and if the bomb is exploded atmospherically, underground, underwater, or at the groung level and there are different sections go to this website it will help
http://www.pbs.org/wgbh/amex/bomb/sfeature/mapablast.html
http://3ammagazine.com/magazine/issue_4/articles/nuclear_bomb_effects.html
hope this helps good luck!!
2007-02-08 12:38:58 · answer #3 · answered by FutureRadiologist14 3 · 0⤊ 0⤋
Lots
2007-02-07 12:28:36 · answer #4 · answered by muffbro 2 · 0⤊ 0⤋
It all depends on the yield of the bomb... how many kilo-ton yield it is.
2007-02-07 12:40:00 · answer #5 · answered by MadMaxx 5 · 0⤊ 0⤋