3 sides, L, W, W
L+W+W = 680
L= 2W
2W+W+W = 680
4W = 680
W = 680/4
W = 170
L = 170*2 = 340
2007-02-07 04:23:58
·
answer #1
·
answered by Grant d 4
·
0⤊
0⤋
Let a be the width. Then the length is 2a
For two widths and one length.
2*a + 2a =680. So 4a = 680, therfore a = 170. The pasture has a width of 170, and a length of 340.
For two lengths and one width,
a + 2*2a = 680. So 5a = 680, therefore a = 136. The width is 136, and the length is 272.
Depends what side the river runs on...
2007-02-07 12:28:25
·
answer #2
·
answered by abdotzed 3
·
0⤊
0⤋
680 ÷ 2 = 340 = Length
340 ÷ 2 = 170 ft (width, each end)
= 3 sides of the pasture 340ft by 170ft
2007-02-07 12:27:46
·
answer #3
·
answered by Norrie 7
·
0⤊
0⤋
So, the fence has three sides.
The pasture is twice as long as it is wide.
So, width is X, Length is 2X.
Fence length is X + 2X + X = 4X
680/4X = 170 feet
the pasture is 170 x 340
2007-02-07 12:23:24
·
answer #4
·
answered by les 4
·
0⤊
0⤋
I get L&W are 340' and 170' when the river is along a length, and L&W are 272' and 136' when the river is along a width. Sorry - the question is ambiguous!!
2007-02-07 12:35:05
·
answer #5
·
answered by Jim C 1
·
0⤊
0⤋
Length = 2x
Width = x
2x + 2x + x + x = 6x (because pasture has 4 sides, cannot take a side away, thats impossible)
5x, if width on river side
4x, if length on river side
IF WIDTH ON RIVER SIDE:
5x = 680
x = 136
length (of one side) = 272 feet
width (of one side) = 136 feet
IF LENGHT ON RIVER SIDE:
4x = 680
x = 145
length (of one side) = 290 feet
width (of one side) = 145 feet
2007-02-07 12:33:25
·
answer #6
·
answered by F.V 2
·
0⤊
0⤋
the width of the two sides is 170 the length of the long side is 340.
2007-02-07 12:24:03
·
answer #7
·
answered by call_me_LaLa 6
·
0⤊
0⤋
Let width be x
So, x+x+2x = 680
or 4x = 680
or x = 170 feet
2007-02-07 12:26:19
·
answer #8
·
answered by ag_iitkgp 7
·
0⤊
0⤋
Yo didn't specify if the river runs allong the lenght or width whivh is a problem, im assuming length
680=2W+L
2W=L
thus
680=L+L=2L
L=340
W=170
2007-02-07 12:23:16
·
answer #9
·
answered by Anonymous
·
0⤊
0⤋