A=P+PRT (A=1000) (P=50) (R=.06)
2007-02-07 03:16:49 · 6 answers · asked by CHAVOYA J 1 in Science & Mathematics ➔ Mathematics
to answer these types of questns, you have to first subt. the values of the constants ie de alphabts into the eqn
A=P+PRT
1000=50+(50)(.06)(T) , FOR THIS, WE ARE SOLVING FOR T
1000-50=50*.06*T , grouping like terms
950= 3*T
950/3=T the 30 crossing the equal sign to divide bcos
it was multiplying to T
T=316.6667
therefore the answer is gonna be the rounding expecting frm the teacher.
2007-02-07 03:57:12 · answer #1 · answered by Prince 1 · 0⤊ 0⤋
The only unknown is T so one way to solve the problem is to isolate T and then substitute like so:
A-P=PRT
T=(A-P)/PR
and substituting,
T=(1000-50)/(50)(.06)
or T=950/3 or T= 316.7
2007-02-07 03:41:05 · answer #2 · answered by Anonymous · 0⤊ 0⤋
1000 = 50 + (50)(.06)T
1000 = 50 + 3T
1000 - 50 = (50 + 3T) - 50
950 = 3T
950/3 = 3T/3
316.66666666666666 = T
2007-02-07 03:31:43 · answer #3 · answered by Huh? 3 · 0⤊ 0⤋
just plug in the given values and solve for the unknown
1000=50 +50(.06)T
950/3 = T
T= 316.666............
2007-02-07 03:30:01 · answer #4 · answered by bignose68 4 · 0⤊ 0⤋
1000=50+50(0.06)T
1000=50+3T
1000=53T
18.87=T
2007-02-07 03:22:28 · answer #5 · answered by Mysterious Ways 1 · 0⤊ 0⤋
1000=50+50*0.06*T
950=3T
T=950/3
T=317
2007-02-07 03:22:58 · answer #6 · answered by iyiogrenci 6 · 0⤊ 0⤋