the derivative of: f(x)= 8[arcsin(x/4)] - [x((16-x^2)^1/2))]/2?

Question

That is: 8 times arcsin of x/4 minus "x" times the square root of 16 minus x^2 divided by 2.......... help!

Answer 1

2(1-(x/4)^2)^(-1/2) + (x^2)(16-x^2)^(-1/2)/2 - (16-x^2)^(1/2)/2