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How do I find the standard deviation of a random number uniformly distributed between 0 and 1....

How about between 0 and 5, etc.

2007-02-07 01:26:32 · 2 answers · asked by Steven 2 in Science & Mathematics Mathematics

2 answers

Given a uniform distribution, this means that the probability density function is going to be a constant over the range of possible values. You also know that the integral of the pdf over the entire range of possible values must be 1. So:

f(x)={c where a≤x≤b, else 0}
[a, b]∫c dx=1
cx|[a, b]=1
cb-ca=1
c(b-a)=1
c=1/(b-a)

So for the range 0 to 1, your pdf would be f(x)={1 where 0≤x≤1, else 0}. And for the range 0 to 5, you have f(x)={1/5 where 0≤x≤5, else 0}

Now you find the mean, which is the integral of x*f(x) over the range of possible values. So:

E(x)=[a, b]∫x/(b-a) dx
1/(b-a) [a, b]∫x dx
1/(2b-2a) (x²|[a, b])
1/(2(b-a)) (b²-a²)
(b-a)(b+a)/(2(b-a))
(b+a)/2

(This result should be thoroughly unsurprising, since it simply states that the mean of a uniform distribution between two points is the average of those two points)

Now you remember the formula for variance:

σ²=E((x-E(x))²)

There is a simple computational formula for this, which you may have memorized, but which I will derive here:

E((x-E(x))²)
expand the square:
E(x²-2xE(x)+E(x)²)
Use linearity of expected value:
E(x²) - E(2xE(x)) + E(E(x)²)
Using linearity of expected value and the fact that expected value of a constant is that constant (in particular, E(E(x)²)=E(x)²):
E(x²) - 2E(x)E(x) + E(x)²
Simplifying:
E(x²)-E(x)²

So now we must find E(x²):

[a, b]∫x²/(b-a) dx
1/(b-a) [a, b]∫x² dx
1/(b-a) (x³/3 |[a, b])
1/(3(b-a)) (b³-a³)
(b-a)(b²+ab+a²)/3(b-a)
(b²+ab+a²)/3

Now, using the formula for variance:

σ²=(b²+ab+a²)/3 - ((b+a)/2)²
σ²=(b²+ab+a²)/3 - (b²+2ab+a²)/4
σ²=(4(b²+ab+a²) - 3(b²+2ab+a²))/12
σ²=(b²-2ab+a²)/12
σ²=(b-a)²/12

Now, the standard deviation is just the square root of that:

σ=(b-a)/√12

So for the range 0 to 1, the standard deviation is just 1/√12. And for 0 to 5, it is 5/√12. You can go ahead and memorize this formula if you want, but I think the process used to derive it will be more useful to you in the long run.

2007-02-07 06:19:05 · answer #1 · answered by Pascal 7 · 0 0

SD = Mean - Actual

2007-02-07 01:31:17 · answer #2 · answered by Fbfbfbfb 2 · 0 0

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