I am having trouble with this can anyone help, please read bleow?

Question

Question is:
Determine graphically the vertices of the triangle, the equation of whose sides are given as y=x; y=o; 2x + 3y = 10. Interpret the results.

I am having trouble figuring out the whole thing, I am not good at this can anyone help. Please

Answer 1

Here's what it is asking you to do. It wants you to find the triangle that is in the graph, and it has three sides. The first side, y=x, means that a line going through all points where x and y are equal. So, first, draw a line through (0,0), (1,1), (2,2), etc. The second line, y=0, will be your horizontal axis. The third side will be the limiting factor. Since you know that it is a line and that it will intersect with the other two, you need to figure out where these intersections occur. So, first, plug y=0 into your equation. This gives 2x=10, so x=5, so the line goes through (5,0). The other end of the line will fall on the y=x line. So, find the point where x and y are equal in the last equation. Doing it algebraicly, here is how it would look.

2x+3y=10
x-y=0. This becomes 2x-2y=0.

So, subtracting, you get 5y=10, so y=2. The line crosses the other line at (2,2). So your third line is found by drawing a straight line between (5,0) and (2,2).

Hope this helps.

Answer 2

it would be y=2 hope it helps