2007-02-07 00:27:26 · 3 answers · asked by sudeep v 1 in Science & Mathematics ➔ Chemistry
De broglie eqn was given by broglie
it is a relation between momentum and wavelength of a minute particle like electrons etc ...
wavelength = h/p
h - planck constant = 6.626 * 10^-34 Js
p- momentum of particle
2007-02-07 00:36:35 · answer #1 · answered by abhi19 1 · 0⤊ 0⤋
In physics, the de Broglie hypothesis is the statement that all matter has a wave-like nature (wave-particle duality). The de Broglie relations show that the wavelength is inversely proportional to the momentum of a particle and that the frequency is directly proportional to the particle's kinetic energy. The hypothesis was advanced by Louis de Broglie in 1923 in his PhD thesis; he was awarded the Nobel Prize for Physics in 1929 for this work, which made him the first person to receive a Nobel Prize on a PhD thesis.
2007-02-07 00:34:47 · answer #2 · answered by Deepthi 1 · 0⤊ 0⤋
lambda=h/mv
where h = plank's constant
m = mass
v = velocity of mass
2007-02-07 00:30:29 · answer #3 · answered by n nitant 3 · 0⤊ 0⤋