The sum of the digits of a two-digit number is 11. The ones digit is 5 more than twice the tens digit.?

Question

What is the number

Answer 1

let the no. in ones place b "y"
n that in tens place b"x"
therefore
x+y=11
n
y=2x+5
solving,
x=9
n
y=2
hence no. in 29

Answer 2

it truly is termed a equipment of eqations. There are 2 equations, both with 2 unknowns (enable's call them X and Y). The X interior the first equation is an similar because the X interior the 2d equation, similar for the Y's. So, if we remedy between the equations for X in words of Y we may be able to replace X interior the 2d equation and remedy for the single last unknown. Whew! ok, what are our 2 equations? we do not comprehend both digit so our 2 digit huge variety sounds like XY. First, they say the sum of both digits is eleven. So X + Y = eleven, no longer too complicated. next, they say those digit (Y) is 5 better than two times the tens digit (X). So Y = 2X + 5. Bit trickier, yet conceivable. So right it truly is our equipment of equations : X + Y = eleven Y = 2X + 5 Hmm, Y is already solved for in that 2d one so enable's replace Y interior the first one. that receives us to at least one unknown so that you'll remedy. X + ( 2X + 5 ) = eleven 3X + 5 = eleven 3X = 6 X = 2 to remedy for Y we ought to plug this X fee lower back into the different equation, no longer the single we only solved. Y = 2( 2 ) + 5 Y = 4 + 5 Y = 9 So, our secret 2 digit huge variety is 29. this technique is termed substitution and could be used for as many unknowns as you pick see you later as you've that many various equations.

Answer 3

let the digits be x and y respectively;x-the ones n y the tens

x+y=11 ..........eqn 1
x=5+2y ..........eqn 2
subtitute the value of x of eqn 2 into eqn 1

(5+2y)+y=11
5+2y+y=11
5+3y=11
3y=11-5
3y=6
y=6/3
y=3
subt. the value of y into eqn 1
x+3=11
x=11-3
x=9
therefore, the number is 92.

proof:(condition 1)

sum of the digits 9+2=11

(condition 2 )
the ones digit is 5 more than twice the tens digit;
the ones digit which is 9 is 5 more than twice of 2 which is 4
ie 9-4=5.

Answer 4

29

Answer 5

Let the number be xy and from the given conditions:-
y = 2x + 5
x + y = 11

x + 2x + 5 = 11
3x = 6
x = 2
If x = 2, y = 9
Number is 29

Answer 6

let ones digit be x and tens digit be y
then
x + y = 11
x= 2y + 5
solve these simultaneous equations
you will get the answers as x = 9 , y =2

Answer 7

x+y=11
y=2x+5

x+2x+5=11
3x+5=11
3x=6
x=2

2+y=11
y=9

The number is 29.

Check:
2+9=11
11=11

9=2(2)+5
9=4+5
9=9

Answer 8

ab

a+b=11
b=2a+5

a+(2a+5)=11

3a=11-5
3a=6
a=2

b=2.2+5
=4+5
=9

the number is 29