Can you slove this for me and explain how you did it? I need help!?

Question

find the equation of the line that contains the point whose coordinates are (1,2) and has a slope -1.

Answer 1

y-2/x-1=-1

solve and get the result
i have used point slope form

y-y1/x-x1=m(slopoe of line)

Answer 2

the eqn of any line is given as y=mx+c,where y is the y value of the point and x is the value of the point, m is the gradient(slope) and c is the y intercept (ie, the point where the line cuts the y-axis).
according to the qtn, x=1, y=2 and m=-1 but c cannot be found. so subtituting the values into the eqn to solve for c,

y=mx+c, 2= -1(1)+c
2= -1+c ,multiplying -1 and1
2+1= c ,grouping like terms,-1 crosses the equal sign an it bcomes positive.
3=c ,adding 2 and 1 to get answer for c.

therefore, c (the y intercept) = 3

THEREFORE THE EQN OF THE POINTS WHOSE COORDINATES ARE (1,2) AND HAS THE SLOPE -1 IS

y=-1x +3
ie y=-x+3, bcos -1x is written -x


For further explanation, u can write to me at [e-mail]

Answer 3

1) The standard form for the equation of a straight line is y = ax+b; where, by definition, a is the slope of the line and b is the y-intercept (i.e., the value of y when x equals zero).

2) In your case, a is given (-1), and b = y-ax = 2-a = 2-(-1) = 3

Answer 4

To solve this, recall the slope formula.

(y2 - y1) / (x2 - x1) = m

To solve this, all you have to do is plug in (1,2) for (x1,y1), and (x,y) for (x2, y2). Also, plug in m = -1 (since m represents the slope, and we're given the slope). Therefore, the above equation becomes

(y - 2) / (x - 1) = -1

Multiplying both sides by (x - 1), we get

y - 2 = (-1)(x - 1)

Expanding the right hand side,

y - 2 = -x + 1

Moving the -2 to the right hand side,

y = -x + 3

This is the form we want, because this is in slope-intercept form, or y = mx + b form.

Answer 5

there is a formula for finding the equation of a straight line which passes through a given point (x1,y1) and a given slope m

then the equation is

(y-y1)=m(x-x1)

from this

the line passing through (1,2)
and slope is -1

there fore

y-2 = -1(x-1)
y-2=-x+1
y+x-2-1=0
x+y-3=0
is the required line

Answer 6

the equation for the line is

y - y0 = m(x-x0) where x0,yo are coordinates of the given point, i.e. 1,2, and m is the slope - -1

y - 2 = -1(x-1)

y = -1(x-1) + 2

y = -x + 3

Answer 7

You could use the point-slope form equation

y-y1=m(x-x1)

where
y1=y coordinates of the point
x1-x coordinates of the point
m=slope of the line

so, using this to answer your problem

y-2=-1(x-1)

y-2=-x+1

y=-x+3

hope this helps. =)

Answer 8

nicely what huge variety has factors of two, 3, and four?? The #12. So i'd recommend making each and each and every fraction with that denominator. so that you get: 9/12 - 8/12 + (6/12 + 4/12) = a million/12 + 10/12 = eleven/12 So no pick to shrink the fraction, that is already in simplest (lowest) words.

Answer 9

use the point-slope form. y-y1 = m(x-x1)

m = -1
(x1, y1) = (1, 2)

Putting those values in:
y - 2 = (-1)(x - 1)

Simplifying:
y - 2 = -x + 1

Add 2 to both sides:
y = -x + 3 (slope-intercept form)

Add x to both sides:
x + y = 3 (standard form)

Answer 10

(y-2)/x-1) = 1/(-1)

1(x-1)=(-1)(y-2)
x-1=-y+2

y=(-x)+3

slope = (-1), y-intercept = 3