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if g(x)=6+x+8e^(x-4)

find inverse of g(18)

2007-02-06 17:41:51 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

g(x)=6+x+8e^(x-4)
y = 6 + x + 8e^(x-4)
swap x and y
x = 6 + y + 8e^(y-4)
h(y) = 6 + y + 8e^(y-4)
h(18) = 6 + 18 + 8e^14
inverse of g(18) equals 9620858.3...

Th

2007-02-06 17:57:25 · answer #1 · answered by Thermo 6 · 0 0

That's easy.

But I bet what the question really asked for is "g inverse of 18"

And how would I solve that? Well, the only X I can think of for which the RHS is even rational, let alone an integer, is the one in which the e winds up being raised to the power 0. I.e., X = 4. Plug that in and hope to get lucky.

2007-02-07 01:54:38 · answer #2 · answered by Curt Monash 7 · 0 0

g^-1(x) = 6x + (1/2)x^2 * 8e^(x-4)

so g^-1(18) = 9.6211x10^6

is that what you were asking?

2007-02-07 01:54:33 · answer #3 · answered by R D 2 · 0 0

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