2007-02-06 16:35:29 · 11 answers · asked by Angel eyeZ 1 in Education & Reference ➔ Homework Help
Let's number the equations:
1. x-y=2
2. 4x-3y=11
In the 1st equation, solve for either x or y. In this case, x would be easier. So you add y to both sides (since y is negative). You get:
x=y+2
Now, plug that in for x in equation 2.
4(y+2)-3y=11
Distribute the 4.
4y+8-3y=11
Collect like terms.
y+8=11
Minus 8 from both sides.
y=3
And that's your answer!
2007-02-06 16:45:05 · answer #1 · answered by luv_2eat_chocolate 3 · 0⤊ 0⤋
We simply find out what x is in terms of y for the first equation....
x = 2 + y
Then we substitute 2 + y into x in the other equation:
4(2 + y) - 3y = 11
8 + 4y - 3y = 11
y = 3
Then substitute 3 back into the first equation for y.
Getting
x - 3 = 2
x = 5
2007-02-06 16:41:46 · answer #2 · answered by Anonymous · 1⤊ 0⤋
set: x = y+2
4x = 3y + 11; 4y + 8 = 3y + 11; y = 3
therefore x = 5
2007-02-06 16:41:33 · answer #3 · answered by whoops :) 5 · 0⤊ 0⤋
x=5 and y=3
2007-02-06 19:52:37 · answer #4 · answered by Anonymous · 0⤊ 0⤋
you only multiply both side through 4 to get rid of the fraction, and then you'll divide through 3. x + a million/3y = -eleven x = -a million/3y - eleven or a million/3y = -x - eleven y = -3x - 33 3x/4 - y/2 = -15 3x/4 = y/2 - 15 3x = 4y/2 - 60 3x = 2y - 60 x = 2/3y - 20 or -y/2 = -3x/4 - 15 y = 6x/4 + 30 y = 3x/2 + 30.
2016-11-25 21:41:11 · answer #5 · answered by ? 4 · 0⤊ 0⤋
x-y = 2, therefore x = 2+y ----(1)
4x-3y = 11 ---(2)
Subs (1) into (2)
4 (2+y) - 3y = 11
8 + 4y-3y = 11
y = 3, using (1), x = 2 + 3 = 5
2007-02-06 16:46:08 · answer #6 · answered by knowerofallthings 3 · 0⤊ 0⤋
4x=11+3y
x=(11+3y)/4
(11+3y)/4 - y = 2
multiply by 4
11+3y-4y=8
-y=8-11
y=3
x-3=2
so x=5
2007-02-06 16:45:34 · answer #7 · answered by sheed 1 · 0⤊ 0⤋
y=x-2 y= -- 4/3x - 11/3
2007-02-06 16:41:45 · answer #8 · answered by smileybug_2010 2 · 0⤊ 0⤋
4x-4y=8
4x-3y=11
y=3
x=5
2007-02-06 16:58:40 · answer #9 · answered by khjsc2006 1 · 0⤊ 0⤋
Do it the same way you did the other one.
2007-02-10 15:26:41 · answer #10 · answered by someadvice 3 · 0⤊ 0⤋