I have to express these two equations in the form y=mx+c.
1. 4y-5=2x+5
2. 3(x-1)=4(y+2)
These are my steps for number 1:
4y-5=2x+5
4y=2x+10
4y/4=2x/4+10/4
y=1/2x+10/4
Note: Is this correct? Do I leave the fractions as fractions or make them into decimals? the symbol / is divide by. Thankyou.
2.
3(x-1)=4(y+2)
3x-3 =4y+8
3x+5=4y
4y=3x+5
4y/4=3x/4+5/4
y =3/4x+5/4
Note: Is this correct? Are both of these in the correct form of y=mx+c? Thankyou!
2007-02-06 16:31:08 · 9 answers · asked by Need advice quick... 1 in Science & Mathematics ➔ Mathematics
whoops..I wrote correctly on my paper (second equation..I needed to subtract the 8 from each side). I know that. It was an error. Sorry!
2007-02-06 17:38:48 · update #1
3(x-1)=4(y+2)
3x-3=4y+8
3x-11=4y
4y=3x-11
4y/4=3x/4-11/4
y=3/4x-11/4
Is this correct? Does the x go straight after the 3/4 when I write it on paper?
2007-02-06 17:42:21 · update #2
I'd leave the coefficients as fractions, as it's the normal convention. Fractions are always exact, whereas if you had to write something like "1/3" as a decimal, you'd have to round it, and thus have some inaccuracy. You just might want to make it clear in your writing that "1/2x" means "(1/2)x" and not "1/(2x)". I know it's harder to type it accurately than just write it by hand.
The first one looks right. But in the third step of the second one, it should acutally be 3x - 11 = 4y because you're subtracting 8 from both sides.
2007-02-06 16:37:02 · answer #1 · answered by Anonymous · 0⤊ 0⤋
1. y=1/2*x + 10/4 is correct, but you might want to reduce 10/4. :) It doesn't matter whether you leave them as fractions or decimals, as long as the fraction is reduced, unless your teacher has specified to leave them as fractions or decimals.
2. You are correct up to the second step:
3x-3 = 4y+8.
When you isolate the 4y, you are subtracting 8 from both sides, and (-3) - 8 = -11, not 5. Just fix that and you should get the right answer.
2007-02-07 00:38:30 · answer #2 · answered by Q 2 · 0⤊ 0⤋
You have the method correct. Solution 2 has an error in it. Step 3 should be 3x-11=4y. Continue solving from there.
2007-02-07 00:42:23 · answer #3 · answered by Daniel and Fang Fang in China 2 · 0⤊ 0⤋
A. The general idea is totally correct. You understand what you're doing. Congrats!
B. 10/4 should be reduced to 5/2.
C. Check the step where you subtracted 8 from both sides.
D. Fraction, decimal -- they mean the same thing. Fraction is usually the accepted notation, but it wouldn't be wrong either way.
2007-02-07 00:36:20 · answer #4 · answered by Curt Monash 7 · 0⤊ 0⤋
the 1st one is correct..but u made a slight mistakein de 2nd one :
3(x-1)=4(y+2)
3x-3 =4y+8
3x-5=4y
4y=3x-5
4y/4=3x/4-5/4
y =3/4x-5/4
here....the value of c is -5/4
2007-02-07 00:41:28 · answer #5 · answered by nUssie.. 2 · 0⤊ 0⤋
Yes looks good. Leave as fractions unless the teacher says other wise. But either way its correct.
2007-02-07 00:42:18 · answer #6 · answered by Joshua B 1 · 0⤊ 0⤋
Good work. You are totally correct. The only cruticism is that we usuallybsay y = mx +b, and not y=mx +c. This is a nit , so don't worry about it.
2007-02-07 00:40:59 · answer #7 · answered by ironduke8159 7 · 0⤊ 0⤋
Wow!! Better you than me to have to figure all of that out. My brain fried after the first sentence.
2007-02-07 00:55:22 · answer #8 · answered by grannywinkie 6 · 1⤊ 0⤋
It looks like you've done it correctly to me.
2007-02-07 00:37:55 · answer #9 · answered by kellenraid 6 · 0⤊ 0⤋