What is the relationship between a right angle & a rectangle formed from it. Explain two ways to find the area of a right angle.
2007-02-06 16:27:23 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Sorry I don't remember much from highschool but hope this helps - a right angle is two points intersecting at 90 degrees. A right angle triange has a ninety degree angle and two acute angles (I think that's what they're called - smaller than 90 degree angles anyways.) One way to find the area of a 90 degree triangle would be to multiply both sides coming off the 90 degree angle by each other and divide by two. Because multiplying them by each other would give you the size of a box created by them, and the triangle would be half that box. Sorry that's the best I can do, I know the Pythagoras theorem is the other way but I can't remember that! :) Luck
2007-02-06 16:33:22 · answer #1 · answered by Anonymous · 0⤊ 0⤋
A right angle is a 90 degree angle. A rectangle is formed from 4 right angles.
You can't find the area of an angle. I think you're looking for the area of a rectangle. You can use length x width, or you can use trigonometric functions using the diagonal and one of the interior angles (not the right angle), or you can use definite integrals (you probably don't know what that is)
2007-02-07 00:32:23 · answer #2 · answered by Anonymous · 0⤊ 0⤋
You probably mean 'explain two ways to find the area of a right triangle'...
If you slice a rectangle diagonally, you will end up with two right triangles, with angles 45, 45, and 90 degrees, respectively. The fact that the triangle has a 90 degree angle means that it is a 'right triangle'.
If the area of the rectangle is L*W, you effectively sliced that area in half, so the area of the right triangle is thus 1/2*L*W of the triangle. This is usually denoted as 1/2*b*h, where b is the base of the triangle and h is the height of the triangle.
Another way to find the area of a right triangle (in calculus terms) would be to integrate the function that defines the hypotenuse of the triangle over the length of the triangle... my mind rarely thinks in elemental terms anymore, heh.
2007-02-07 00:37:56 · answer #3 · answered by vaca loca 3 · 0⤊ 0⤋
This doesn't make any sense. You can't find the area of an angle. Rectangles must have right angles or they aren't rectangles.
Look at the problem again.
2007-02-07 00:33:41 · answer #4 · answered by smartprimate 3 · 0⤊ 0⤋
A rectangle formed from a right triangle has twice the area of the right triangle.
The area of a right triangle( I believe you meant triangle and not right angle) is equal to the product of the two legs divided by two.
The area of a right triangle with hypotenuse c and legs a and b is equal to sqrt(s(s-a)(s-b)(s-c)), where s = (a+b+c)/2.
2007-02-07 00:49:50 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋
Angles don't have area. You probably misheard/misread the problem.
2007-02-07 00:31:19 · answer #6 · answered by Curt Monash 7 · 1⤊ 0⤋
You can't find th e area of a Rt. angle, hon, But you can if it were a rt triangle....
2007-02-07 00:33:38 · answer #7 · answered by April 6 · 0⤊ 0⤋