Chem question i think about ideal gas law? not sure?

Question

Heres the question. plz explain how to do it also

Ideal gas law: PV=nRT
(*=degrees)
A mass of 5g of solid(specific heat 2.08 J/g.K) initially at 100*C is droppe into a beaker containing 100g of water (specific heat 4.18 J/g.k) initially at 25*C. Assuming that the heat lost by the solid is gained by the water body, find the final temperature of the system (water + solid).

a)26.8*C
b)30.2*C
c)36.8*C
d)50.0*C

Answer 1

Ideal gas law only applies to gases, not liquids and solids. Here the heat lost by the solid = the heat absorbed by water
5gx2.08J/g.Kx(100*C-T)
=100gx4.18J/g.Kx(T-25*C)
...
T=26.82*C
So the answer is a).

Answer 2

I dont feel like working out all the actual math. SHC of the solid is about half that of the water so the temp change twice as much

difference between temps is 75 degrees. so thats 25 degrees for the water and 50 degrees for the solid. so thats 'd'

btw the equation for this mC'delta'(change)T= mC'delta'T
where 'm' is the mass, C is the specific heat capacity. and delta T is the change in temperature

Answer 3

There are no gases involved in this question. Therefore, the gas laws do not apply.