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A mechanic has found that a car, with a 16-quart radiator has a 40% antifreeze mixture in the radiator. He has on hand a 70% antifreeze solution. How much of the 40% solution would she have to replace with the 70% solution to get the solution in the radiator up to 50%?

2007-02-06 15:17:28 · 2 answers · asked by turbosupra11 1 in Science & Mathematics Mathematics

2 answers

x = the amount of 40% fluid to use
16-x = the amount of 70% fluid to use

Here is the equation you need to use:

.4x + .7(16-x) = .5(16)

2007-02-06 15:25:41 · answer #1 · answered by Bauercvhs 4 · 0 0

.4 *16 +.7*x = (16+x)* .5
6.4 + .7x = 8 + .5x
.2x = 1.6
x = 8 quarts

2007-02-06 23:29:14 · answer #2 · answered by ironduke8159 7 · 0 0

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