the output of a northern gold mine has remined constant at 22 000 ounces per year. At the end of last year, the total output of the mine was 90 000 ounces of gold.
What will the total output be at the end of this year? at the end of next year?
(can you show me how you got this answer.. thank u)
2007-02-06 15:00:32 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
If I understand the question correctly and output remains at 22,000 ounces per year:
90,000 + 22,000 = 112,000 at end of this year
112,000 + 22,000 = 134,000 at end of next year
2007-02-06 15:06:42 · answer #1 · answered by Anonymous · 0⤊ 0⤋
No I cannot.
If the output remains constant at 22,000 /year then output = 22,000 * y where y = the number of years.
Therefore the total output was 90,000 ounces which is 90,000/22000= 4.090909 per year.
Thus the mine exceeded its constant rate by 12,000 ounces.
Thus your premise that the mine has a constant rate o f 22,00 ounces per year is false.
There is no solution to this impossible problem.
2007-02-06 15:20:00 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
They've gotten 90,000 ounces of gold from the mine so far. Each year they get another 22,000 ounces. So the total in another year would just be 90,000 + 22,000 = 112,000. At the end of next year, it will be 22,000 more ounces they can add to the total, bringing the total to 134,000.
2007-02-06 15:05:24 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The first year did not count because they only did 2,000. The following years they did 22,000 per year, so for this year, 5 x 22,000 plus 2000 = 112,000. Next year it will be 6 x 22,000 or 132,000 plus 2000 = 134,000.
2007-02-06 15:15:54 · answer #4 · answered by God+JB=<3 2 · 0⤊ 0⤋
well, if the total output was 90000 ounces last year, and your output is 22000 ounces/year
that is 90000 oz + 22000 oz/year * 1 year = 112000 oz.
the year after is
90000 oz + 22000 oz/year * 2 years = 134000 oz
2007-02-06 15:07:15 · answer #5 · answered by scott 5 · 0⤊ 0⤋