its a parabola, then plot some points plugging in say -1, 0, 1 for x and y
2007-02-06 14:56:14
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answer #1
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answered by Anonymous
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First graph the parabola y = x^2 - 6x + 9. But instead of drawing the parabola itself as a solid curved, use a dashed line to trace where it would be. This is because y = x^2 - 6x + 9 isn't actually part of the graph; we want the value of y greater than this. Then you have to find out which side of the parabola to shade in, everything inside of the parabola or outside of it. Pick a point like (0,0) to see if it fits the inequality. If it does, then the side containing (0,0) is shaded. If not, then it's the other side that has to be shaded in.
2007-02-06 15:02:06
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answer #2
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answered by Anonymous
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The usual way for y=x^2 -6x + 9, except that the result will be everything "above" but not touching the parabola.
The equation is a "perfect square" with roots of (x =3 and x=3). In other words, the parabola "touches" the x-axis at x =3 and opens "up", like a glass.
2007-02-06 15:00:51
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answer #3
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answered by cattbarf 7
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just graph y=x^2-6x+9 and then shade above the graph =)
2007-02-06 14:59:36
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answer #4
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answered by Anonymous
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