please try this proceed your answer, real quick.
2007-02-06 14:34:34 · 8 answers · asked by ram_mar63 1 in Science & Mathematics ➔ Other - Science
you have a 6 digit base 36 number The total liscense plates that can be issued uniquely is (36 ^^ 7) -1 = 78364164095 = ZZZZZZ base 36 (Ya it's a sleeper...)
2007-02-06 14:37:55 · answer #1 · answered by walter_b_marvin 5 · 0⤊ 1⤋
With no spaces allowed (i.e. must contain 6 characters):
Combinations
= (36)*(36)*(36)*(36)*(36)*(36)
= 2176782336 (just more than 2 billion)
With the spaces allowed, it becomes:
Combinations
= (37)*(37)*(37)*(37)*(37)*(37)-1
= 2565726408 (just over 2.5 billion ... the -1 is because you have to have at least 1 digit, they can't ALL be spaces!)
Restricting the combinations to 3 letters and 3 numbers (in any order), and no spaces:
Combinations
= (26)*(26)*(26)*(10)*(10)*(10)
= 17576000 (about 17.5 million)
Up to 3 letters, 3 numbers and spaces
Combinations
= (27)*)(27)*(27)*(11)*(11)*(11)-1
= 26198072 (a little over 26 million - and no 'blank' plates!)
All of these allow some level of duplication; for example, the plate "_ _ A _ _ _" is not considered the same as "_ _ _ A _ _".
2007-02-07 09:28:31 · answer #2 · answered by CanTexan 6 · 0⤊ 0⤋
I believe that in a license plate you can use the characters more than once. So the answer would be 36 to the 6th power possible combinations (36 possibilities in each slot). And, that's assuming that all six slots will be filled with a character.
2007-02-06 23:47:06 · answer #3 · answered by David T 4 · 0⤊ 0⤋
roughly 1 quadrillian^2 possibilities. That's why they let you have A-Z and 0-9 with 6 characters. There's a lot of possibilities
2007-02-06 22:47:26 · answer #4 · answered by Flash Stardust 1 · 0⤊ 1⤋
Calculate the number of combinations and permutations of 36 objects taken 6 at a time.
1947792 combinations
1402410240 permutations
You didn't specify if they could be used more than once.
2007-02-06 22:49:44 · answer #5 · answered by Anonymous · 0⤊ 0⤋
If you completed the question, we could be quick. But you have something missing, such as if there is any restriction on the characters which are letters and numbers.
2007-02-06 22:38:45 · answer #6 · answered by cattbarf 7 · 0⤊ 1⤋
Here's a few possibles.....depending on what you're trying to get at....
6ULDV8 (sexual deviate)
12XLR8 (one to accelerate)
2GR84U (too great for you)
2007-02-06 22:39:41 · answer #7 · answered by Lynn 3 · 0⤊ 1⤋
are you taking a test, or something?
2007-02-06 22:37:57 · answer #8 · answered by rowboat 2 · 0⤊ 1⤋