Draw three resonance structures for SO3? Help I am about to die from trying to figure this out?

Answer 1

no need to die, my friend

Answer 2

WHEN YOU READ THE STRUCTURES MAKE SURE THE BOTTOM O IN EACH CASE IS BONDED TO THE SULFUR ATOM!

Sulfur trioxide:

O=S=O
II
O

The structure is really trigonal planar;. The reason the
the molecule can exist like this is because sulfur has an expanded octet to allow twelve electrons. Anyway, notice how all of the oxgens have a lone pair (two pairs actually) on them. This pair of electrons can be "pushed" to create a structure that looks something like this:
-O-S=O.
III
O+
You can now take the electrons of the negative charge and draw another structure like this:

O=S-O-
III
O+

Anyways, you can keep doing this until all possible resonance structures have been exhausted. Please note, however, that these resonance structures do not contribute much at all to the overall structure of SO3. That is, SO3 is not a hybrid of all of these resonance forms. These are resonace forms that make a minor, if not negligible contribution, and most of the time, you would not include these.

Answer 3

from memory i think that there is a +2 charge on the sulphur. Two of the oxygens with single S-O bonds have a single negative charge. One double S=O bond, the oxygen is uncharged. Hence you have a trigonal planar structure, move the double bond round between the three oxygens and you get the three resonance structures.qed?
Note you cant have S triple bond to oxygen, this would put nine valence electrons on oxygen which is not possible!

Answer 4

First put S in the center and let S electrons be x's and let O electrons be *'s. One S=O bond will be S**xxO. Two more pairs, **, will be on two more sides of O. The other two S-->O bonds will be coordinate covalent bonds. This means that between S and each other O will be xx. Coordinate covalent means that both electrons to be shared will be donated by S. The O's in these bonds will have three pairs of ** on their other three sides. To sum up: There will be one S=O bond and two S-->O bonds. The resonance will be among these three structures, such that one-third of the time, one O will be in a S=O bond.

Now: Doesn't that make your day?

Answer 5

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