m/s in 2 s. What is the total force her harness had to withstand? How many times her weight is this force?
2007-02-06 09:34:29 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
This is modeled using the equation
v=vi+m*g*t-F*t
assuming a constant decelleration
from drawing a free body diagram
from the problem statement
6=50+100*9.81*2-F*2
F=22+100*9.81
=1003 Newtons
j
2007-02-06 09:43:03 · answer #1 · answered by odu83 7 · 0⤊ 0⤋
there are two type of force that act on the person: air drag and the person's weigh
since the velocity is changing, there is an acceleration
Vf=at+Vi
6m/s = a(2s) + 50m/s
-44m/s = a(2s)
a= -22m/s^2
Fnet = ma
Fnet is the sum of forces which are, in this problem, Fair drag and Fweigh
Fair - Fweigh = ma
Fair - (100kg*9.8) = 100kg(22m/s)
Fair - 980N = 2200N
Fair = 3180N
3180/980 = about 3 times her weigh.
2007-02-06 09:47:44 · answer #2 · answered by 7 · 0⤊ 0⤋
Stop doing your homework on YAHOO ANSWERS dumbass...
Please no one help these kids ... it will only make them stupid.
2007-02-06 09:39:00 · answer #3 · answered by Ecofreako 3 · 1⤊ 0⤋