How do i find the x and y intercepts of this equation? How do i properly set the equation up and solve? -2/3y = x I understand you have to subsitute x and y for 0 and solve. But i guess i'm having a problem with the fraction, not so much the concept of intercepts. If u can solve and illustrate how u got there, i would appreciate it.
2007-02-06 09:11:00 · 3 answers · asked by World Expert 1 in Education & Reference ➔ Homework Help
-2/3x = y
the y-intercept is where x = 0:
-2/3(0) = y
0 = y
Since the line crosses at (0,0), the x and y intercepts are both 0.
But let's find the x-intercept anyway. The x-intercept is where y=0:
-2/3 x = 0
-2x = 0*3 = 0
-2x/-2 = 0/-2 = 0
x = 0
(On a side note, any line that has the equation in the form of ax=by has both x and y intercepts of 0. For the intercepts to be other than 0, there must be a constant added, such as ax = by + c).
Hope this helps!
2007-02-06 09:20:23 · answer #1 · answered by disposable_hero_too 6 · 0⤊ 0⤋
To isolate y, multiply each side of the equation with the reciprocal of 2/3, which is 3/2, or 1.5. This leaves you with -y=1.5x, so multiply each side again by -1 to leave y positive and get the equation y= -1.5x. From there you just subsitute 0 to get each intercept. Hope this helps.
2007-02-06 17:22:13 · answer #2 · answered by chocolateviera 1 · 0⤊ 0⤋
-2/3y=x. Ok, first, sub 0 for y. Then the equation is 0=x. Then sub 0 for x. The equation is now -2/3y. Then MULTIPLY by the reciprocle. The eqaution is now y=3/2. So your answer is x=0 and y=1.5.
2007-02-06 17:19:39 · answer #3 · answered by Anonymous · 0⤊ 0⤋