Rate Law... Straightforward Question!?

Question

Consider the reaction with the rate law, Rate = k[BrO3-][Br-][H+]^2

By what factor does the rate change if the concentration of BrO3- is quadrupled and that of Br- is doubled?

Any ideas?

The correct answer is 8.

Answer 1

I havent had general chem in a while but I think it's because the rate law is just a multiplication of concentrations...
So...
if BrO3 is quadrupled....it's 4 times [BrO3]...
and if Br is doubled.... its 2 times [Br-].....

So, 2x4 equals 8, the rate is increased by a factor of 8 times the original.