What's the overall chemical eqn if you add NaOH w/ C6H5NH3+ assuming that the latter & C6H5NH2 (pls. read on)

Question

What is the overall chemical equation if you add [NaOH] with [C6H5NH3+] assuming that the latter & [C6H5NH2] are already present in the solution?

I'm getting something like:

[C6H5NH3+] + [OH-} <==> [C6H5NH2] + [H3O+]

but the H's won't add up...so I'm figuring what's wrong with this equation. Can someone please help and clarify this for me?

P.S. I'm guessing this is a buffer solution right? Because I'm debating wheter its a buffer or a weak base solution.

Answer 1

C6H5NH2 is a base since the nitrogen has a lone pair available and it would 'grab' any H+ in solution and becomes C6H5NH3+. If you add a base what really happens is that C6H5NH2 is formed with the formation of a water molecule. In other word you would drive the reaction to the right hand side:

C6H5NH3+] + [OH-} <==> [C6H5NH2] + [H2O]

Adding more base to C6H5NH2 will not result in any reaction as a base won't react with a base.

Answer 2

C6H5-NH3 + + OH- ===> C6H5-NH2 + H2O