Okay heres the directions: find the slope of the tangent line to the graph of each funion at the given point and deermine an equation of the tangent line.
here's the problems were told to do
f(x)=2x+7 at (2, 11)
f(x)=-3x+4 at (-1, 7)
f(x)=3x^2 at (1,3)
f(x)=-1/x at (3, -1/3)
I dunno how to do this. Help me please.
2007-02-06 06:10:29 · 3 answers · asked by packerswes4 5 in Science & Mathematics ➔ Mathematics
Check out the web link below. The calc section explains it better than me. This is simple differential calc.
2007-02-06 06:20:55 · answer #1 · answered by JC 2 · 0⤊ 0⤋
f(x) = 2x+7 you take the derivative d(f(x)/dx= 2 This is a straight line all the slope is =2. the line is its tangent
The same for f(x) =-3x+4 . It is a straight line .Its slope is -3
F(x) = 3x^2 dF(x) /dx = 6x at a point with abcissa x=1 you replace x by one and find slope =6
f(x) =-1/x = -x^-1 the derivative of x^-1 = -x^-2 and at the point x(3,-1/3) , you replace x by 3 and the slope is 1/6
2007-02-06 14:24:04 · answer #2 · answered by maussy 7 · 0⤊ 0⤋
d{f(x)}/dx would give you the equation of the tangent line to each curve, and then you can substitute the values of the coordinates to find the exact slope.
Here.
1. 2
2. -3
3. 6x-> 6
4. 1/x^2 -> 1/9
2007-02-06 14:22:57 · answer #3 · answered by Nitin Jagga 1 · 0⤊ 0⤋