Cl2(g) ↔ 2Cl(g)
Cl(g) + CHCl3 → HCl(g) + CCl3 (slow)
CCl3 + Cl(g) → CCl4(g) (fast)
a) The overall rate law is equal to the rate law of the second step
as it appears above
b) k1[Cl2] = k-1[Cl]2
c) Cl(g) does not appear in the overall reaction
d) If this is a correct mechanism the observed law would be
Rate = k[Cl2]1/2[CHCl3]
thank you in advance!
2007-02-06
04:50:07
·
3 answers
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asked by
Anonymous
in
Science & Mathematics
➔ Chemistry
There could be more than 1 correct choice. i need everything that is true?
2007-02-06
05:15:59 ·
update #1