That's not a question. Hell, those aren't even words.
2007-02-06 04:48:03
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answer #1
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answered by w00t 3
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Another way to do it, is the following:
7a(2a+0.5) Multiply each term of the first factor by 7a:
14a2 + 3.5a (2 is an exponent)
-0.3(2a+0.5) Multiply each term of the first factor by -0.3:
-0.6a - .15 is the answer. Now add the similar terms of the two products and the final answer is:
14a2 + 2.9a - .15
2007-02-06 05:15:14
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answer #2
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answered by Juingol 3
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Ok use the FOIL method. That stands for First, Outside+Inside, Last.
First terms: 2a*7a=14a^2
Outside plus inside terms:2a*-0.3+0.5*7a
That equals -6/10a+3/1/2a=2/6/10a
Last terms: 0.5*-0.3=-0.15
Solution: 14a^2+2/6/10a-0.15 is believe.
I did that in my head. Just remember FOIL.
2007-02-06 05:02:41
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answer #3
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answered by Zappy91 2
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You need to multiply the two, like this:
(A + B)(C + D) = A*C + A*D + B*C + B*D
So we get:
2a*7a + 2a*(-0.3) + (0.5)*7a + (0.5)*(-0.3)
= 14a^2 - 0.6a + 3.5a - 0.15
= 14a^2 + 2.9a - 0.15
2007-02-06 04:51:03
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answer #4
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answered by untitledonald 2
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(2a+0.5) (7a-0.3) =
14a2 - 2a(.3) + .5(7a) - .15 =
14a2 - .6a + 3.5a - .15 =
14a2 + 2.9a - .15
I hope this is along the line you were asking.
2007-02-06 04:52:02
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answer #5
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answered by chevalier rouge 4
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2016-11-02 12:06:24
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answer #6
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answered by ? 4
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Solve (2a+0.5)(7a-0.3)
First: eliminate parenthesis --- use the Foiling Method...
(2a)(7a)+(2a)(-0.3)+(0.5)(7a)+(0.5)(-0.3)
Sec: combine the terms...
14a^2+(-0.6a)+(3.5a)+(-1.5)
14a^2 - 0.6a + 3.5a - 1.5
Third: combine "like" terms...
= 14a^2 + 2.9a - 1.5a
2007-02-06 05:23:40
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answer #7
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answered by ♪♥Annie♥♪ 6
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(2a+0.5) (7a-0.3) =
14a² -0.6a + 3.5 a - 0.15 =
14a² + 2.9a - 0.15
<>
2007-02-06 04:56:49
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answer #8
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answered by aeiou 7
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(2a+0.5)(7a-0.3)
14a^2 + 2.9a - 0.15 =0
b+/- sqrt b^2-4ac/2a
2.9 +/- SQRT8.41-8.4/28
2.9+/- 0.56/28
a = 0.12 or 0.084
2007-02-06 04:58:45
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answer #9
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answered by Anonymous
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14a^2 - 2.9a - .15
2007-02-06 04:51:43
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answer #10
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answered by Annie M 1
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Factored out it is =14a-0.15
the variable "a" is un-definable do to lack of info.
2007-02-06 04:50:21
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answer #11
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answered by bjd72003 3
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