2007-02-06 04:06:20 · 4 answers · asked by dru 1 in Science & Mathematics ➔ Chemistry
Zn = 65.39 g/mol
Cl = 35.45 g/mol
20 g Zn / 65.39 g/mol Zn = 0.3059 mol Zn
since it's a 1 to 1 ratio and Zn is the limiting reactant:
0.3059 mol Zn = 0.3059 mol ZnCl2
ZnCl2 = 136.29 g/mol
0.3059 mol ZnCl2 x 136.29 g/mol = 41.69 g ZnCl2
2007-02-06 04:21:36 · answer #1 · answered by Anonymous · 0⤊ 0⤋
This is a very standard kind of stoichiometry question. Convert the mass of zinc into moles using the atomic weight. You'll form the same number of moles of zinc chloride (ZnCl2). So, use the molar mass of zinc chloride to convert that number of moles back into grams.
2007-02-06 04:15:52 · answer #2 · answered by hcbiochem 7 · 0⤊ 0⤋
this is a very time-honored type of stoichiometry question. Convert the mass of zinc into moles using the atomic weight. you will sort the comparable sort of moles of zinc chloride (ZnCl2). So, use the molar mass of zinc chloride to transform that kind of moles back into grams.
2016-12-17 03:46:29 · answer #3 · answered by ? 4 · 0⤊ 0⤋
67.3grams
2007-02-06 04:13:33 · answer #4 · answered by Nickey 1 · 0⤊ 0⤋