Please Help Math?

Question

O.k. So I have these problems I need help with

is this right -- (b^4)^5 = ^20

how do I simplyify (7b)^2

How do I multiply (x-1)^2

and lastly is this right

45a^6b^10
--------------
5a^3b^2

= 9a^3b^8 ???

Answer 1

The two you asked if you're right, you are right. (assuming the first one you meant b^20.

(7b)² = 7²b²
(7b)²=49b²

(x-1)² = (x-1)(x-1)
(x-1)² = x² -x -x +1
(x-1)² = x² - 2x + 1 <<<

Answer 2

is this right -- (b^4)^5 = ^20 --- Yes this is correct, it's b^20 because an exponent to the power of another is multiplied

how do I simplyify (7b)^2 --- you square 7, then square b, because the entire quantity 7b is being squared

How do I multiply (x-1)^2 --- you use the foil method (first, outer, inner, last) so you would be multiplying (x-1) * (x-1)

and lastly is this right

45a^6b^10
--------------
5a^3b^2

= 9a^3b^8 ???

yes because you divide the coefficents and subtract the exponents!

Answer 3

first one is right
second is 49b^2
x^2-2x+1
and last one should be
9a^2 2b^8

Answer 4

I think you should check your work....