Help with 3 different square root problems?

Question

(1) sqrt63 - sqrt7

(2) (2xsqrt2x) ( 3sqrt5x)

and finally

(3) (sqrt4x + 4) -12 = 0


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Answer 1

(1) sqrt63 - sqrt7
\/63
63|3
21|3
07|7
1
\/3² * \/7 = \/63 - \/7

(2)
(2xsqrt2x) ( 3sqrt5x) = (2\/2x)(3\/5x) = 6\/10\/x² =
6x\/10 = 6xsqrt10
(3)
(sqrt4x + 4) -12 = 0
\/(4x + 4) - 12 = 0
\/(4(x + 1))² = (12)²
4(x + 1) = 144
x + 1 = 144 : 4
x + 1 = 36
x = 36 - 1
x = 35
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Answer 2

(1) The square root of 63 can be factored to 3 times the sqrt7. So, subtract the sqrt7 and get 2 times sqrt7.

(Factoring can be done with a factor tree 63 = 7*9 = 7*3*3. The 3*3 is then moved to the outside of the squareroot giving you 3sqrt7)

I find the other two equations difficult to decipher. A little better description would be helpful.

Good luck!

Answer 3

the answer is only the sq. root of three. the thanks to do it: Step A) considering which will be written because the fraction 3 over root 3, you first ought to get rid of the novel interior the denominator. you're going to ought to multiply the fraction through some thing. yet because the fraction ought to keep its similar fee, the in common words ingredient you may multiply it through is a million. yet--any fraction the position the numerator and denominators are an similar equals one. So... 3 / root 3 cases root 3 / root 3 = 3 cases root 3 / root 9 B) Take the sq. roots of any perfect squares. 3 cases root 3 / root 9 = 3 cases root 3 / 3 C) part of the fraction above contains 3 divided through 3, that is a million. Divide that out, and all that leaves is the basis 3 interior the numerator. for this reason, the answer is only root 3. Aaah, I ask for forgiveness if I made that truly complicated! that is totally not person-friendly even as i am going to't write out easily fractions and radicals, etc.! wish that helps in a roundabout way! =D

Answer 4

(1) sqrt(63) - sqrt(7) = 7.937 - 2.646 = 5.291

(2) (2xsqrt2x)(3sqrt5x)
x= x^1 or x^ 2/2 and sqrt(2x) = 1.414x^1/2
also sqrt 5x = 2.236x^1/2

substitute these into the original expression and obtain
2x^2/2(1.414x^1/2)3(2.236x^1/2)
multipy the numerical tems and the variable terms. remember to multiply power you simply add exponents
therefor:
(2)1.414(3)(2.236) x^4/2 = 18.97 x^2

(3) (sqrt 4x+ 4) -12=0
sqrt 4x = 12-4 = 8
square both sides: 4x = 64
x = 8

Answer 5

(1) 3 sqrt 7 - sqrt 7 = 2 sqrt 7

(2) 2x3 = 6. and sqrt(2x*5x) = sqrt 10X^2 = X sqrt 10
so answer is 6X sqrt 10

(3) sqrt 4X + 4 = 12. square both sides:
4X + 4 = 144
4X = 140 ............. X = 35