what is the velocity of a 60.0kg jogger with the kinetic energy of 1080.J?

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what is the velocity of a 60.0kg jogger with the kinetic energy of 1080.J?

2007-02-06 01:14:09 · 2 answers · asked by Connie L 1 in Science & Mathematics ➔ Earth Sciences & Geology

2 answers

KE = 0.5 (mass) (velocity)^2

1080 J = 0.5 (60 kg) (v)^2

1 J = 1 (kg)(meter^2)/(second^2)

1080/(0.5*60) = v^2

36 = v^2

6 = v in meters per second

2007-02-06 01:51:59 · answer #1 · answered by Johnny 3 · 0⤊ 0⤋

the velocity of the jogger taking into account friction would be 4.24 meters per second. He would have lost 1.2 x10^-14 kilograms of mass due to friction.

2007-02-06 10:08:50 · answer #2 · answered by goring 6 · 0⤊ 0⤋