2007-02-06 00:47:29 · 7 answers · asked by Joshua U 2 in Science & Mathematics ➔ Mathematics
Here,
In x2+x+1>0
Let coeff. Of x2 be a
coeff. Of x be b
n coeff. Of be c
therefore b2 -4(a)(c)
=1-4(1)=-3<0
therefore eqn. is always >0
therefore ans. Is “all real numbers”
2007-02-06 01:27:38 · answer #1 · answered by Anonymous · 0⤊ 0⤋
remedy the inequality: x2 - 5 > 0? at first, the question could extremely say 2x not x2. 2x - 5 > 0 Secondly, deliver 5 to the different part of the inequality. So, -5 will become +5. Do you spot why? we've: 2x > 5 next: Divide the two factors of the inequality via 2 to remedy for x. very final answer: x > 5/2. What does our answer mean? It potential that notwithstanding the cost of x is, it extremely is larger than the fraction 5/2. i'm hoping this enables. Guido P.S. shop this ideas: whilst multiplying or dividing via a adverse form, you may replace the path of the sign in your very final answer.
2016-12-13 10:09:47 · answer #2 · answered by hergenroeder 4 · 0⤊ 0⤋
x^2 + x + 1 > 0
x^2 + x + (1/2)^2 - (1/2)^2 + 1>0
(x + 1/2)^2 - (1/4 -1) > 0
(x + 1/2)^2 + 3/4 > 0 => this expression is always positive therefore always true since (x+1/2)^2 is always positive and +3/4 is always positive
this is true for whatever value of x you chose so x is any number from - infinity to plus infinity
2007-02-06 01:06:49 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Well,
this equation holds true for all real values of x.
x squared is always positive,
The second term of equation, i.e. x if positive, its easy to see that all terms add to something greater than zero.
If x is negative, then also th result would be the same, because xsquared will take care of the negative value of x alone , so the whole equation is always positive
2007-02-06 00:55:42 · answer #4 · answered by keepsmiling 2 · 0⤊ 0⤋
first of all this is X squared. secondly when x is zero the value of the equation is 1 i.e. greater than zero so when value of x is greater than zero the equation stands. Again when the value of X is negative suppose -1 still the equation shows greater than 1
(-1)2+(-1) +1=1-1+1=1 which is greather than zero and it is true for all negative numbers.
2007-02-06 00:59:48 · answer #5 · answered by tapas 1 · 0⤊ 0⤋
Since anything multiplied by zero is zero, any number used for X should work.
2007-02-06 00:58:00 · answer #6 · answered by geobert24 5 · 0⤊ 0⤋
x2+x>-1
x(x+1)>-1
the answer is the interval [-1,infintie)
2007-02-06 00:57:45 · answer #7 · answered by al_mana3i 1 · 0⤊ 0⤋