express the following statement as a formula with the value of the constant of proportionality determined with

Question

the given conditions: wvaries directly as x and inversely as the square of y. if x=15 and y=5, then w=36

Answer 1

w = k x / y²
36 = k x 15 / 25 = k x 3 / 5
k = 5 x 36 / 3 = 60
w = 60x / y²

Answer 2

a million. W = kx/y^2 then, 36 = ok(15)/5^2 ok = 36(25)/15 = 60 so, W = 60x/y^2 2. P = ok(L)^(a million/2) then 2 = ok(6)^(a million/2) ok = 2/2.449 = 0.816 P= 0.816(L)^(a million/2) a million = 0.816 (L)^(a million/2) L = (a million/816)^2 = a million.502 feet 3. 8x - 12 / 4x - 2 = 2 rem (-8) 4.x^4 - 2/ x -a million = x^3 + x^2 + x + a million, rem = -a million 5. ax^3 + bx^2 + cx +d = 0 at x =a million a + b + c + d = 0 --------------------[a million] at x = 2 8a + 4b + 2c +d = 0 ----------------[2] at x = 4 sixty 4 a + 16 b + 4c + d = 0-----------[3] and x = 0 d = - 16 --------------------------------[4] so, [a million] , [2], [3] will be a + b + c = 16 ------------------------[5] 8a + 4b + 2c = 16 -------------------[6] 64a + 16b + 4c = 16 ---------------[7] [6] - 8x[5] -4b - 6c = -112 -----------------------[8] [7] - 64x[5] -48b - 60c = -1008 ------------------[9] from [8] b = (112 - 6c)/4 sub to [9] -40 8(112 - 6c)/4 - 60c = -1008 -1344 + 72c - 60c = -1008 12c = 1344-1008 c = 28 -----------------------[10] b = (112 - 6(28))/4 = -14----[eleven] a = 16 - b - c =2 so f(x) = 2x^3 -14x^2 +28x - 16

Answer 3

W=kX/Y^2
36=k.15/5^2
k = 60.

Answer 4

w = kx/y^2
36 = k . 15 / 5^2
k = 60

w = 60x/y^2

Answer 5

w= k * x/(y^2)

36=k * 15/25

k=60