Maths Question?

Question

Pls help :

Three tins, A, B and C, contained a total of 240 cookies. Some cookies from A were transferred to B and the number of cookies in B was doubled. Then some cookies from B were transferred to C and the number of cookies in C was doubled. As a result, there was an equal number of cookies in each tin. How many cookies were in each tin at first?

Thanks a million

Answer 1

a+b+c = 240
at the end all equal 80 + 80 + 80

b into c was doubled - C started with 40

move 40 back to B now equals 120

a into b doubled - so B started with 60 and got 60 from A

a ended with 80 +60 to B


A = 140 - moved 60 to B
B= 60 moved 40 to C
C= 40

tada -= had to work it backwards

Answer 2

A+B+C=240

THERE ARE NOW A-B = B+B-C =2C (BECAUSE THERE WERE B COOKIES TAKEN OUT OF A TO DOUBLE B. THEN THERE WERE C COOKIES TAKEN OUT OF B TO DOUBLE C)

SO A-B=B+B-C=2C OR A-B=2B-C=2C

OR A-B = 2B-C AND 2B-C = 2C
2B=3C
A -B=3C-C
A -B=2C
A -1.5C=2C
A=3.5C
A+B+C=240
3.5C+1.5C+C=240
6C=240
C=40
A=3.5C=140
B=1.5C=60