physics
2007-02-05 19:58:09 · 5 answers · asked by klear 1 in Science & Mathematics ➔ Physics
resultant= (modA + modB + 2modA *modB(cos(thrita)))^1/2
2007-02-05 20:05:31 · answer #1 · answered by n nitant 3 · 0⤊ 0⤋
You need more than just the magnitude, you need the angle of one of them. The result is simply the dot product of the two vectors.
Visually, draw one of the vectors. Add the tail of the second one to the head of the first. Then draw a vector from the tail of the first to the head of the second. That's the resultant vector.
2007-02-06 04:03:14 · answer #2 · answered by tony1athome 5 · 1⤊ 1⤋
by parallelogram or triangle law of vector addition
magnitude of resultant is R=(a^2+b^2+2abcost)^1/2 a,b are magnitude of given vectors t is angle between them
2007-02-06 04:08:01 · answer #3 · answered by tarundeep300 3 · 0⤊ 1⤋
Geometrically, use the "parallelogram rule": the resulting vector is the diagonal of the parallelogram constructed by placing the vectors end-to-end. Mathematically, find the x and y components and add them.
2007-02-06 04:03:59 · answer #4 · answered by gp4rts 7 · 0⤊ 1⤋
By parallogram theorem
2007-02-06 04:37:12 · answer #5 · answered by Dilip Dey 2 · 0⤊ 1⤋