give the output of program in c-lang -main() { static intvar=5; printf("%d",var--) if (var) main(); }

Answer 1

Did you make a typo with "var" vs "intvar"??

Assuming you made a typo the output is "54321".

Answer 2

already they have given the answer.

Output would be 54321.

Why?

since the declaration of the variable is static though, we have a decrement var-- and which makes the program to display it 54321.

Answer 3

intvar must be separated
semicolon must be added for print command
Then output will be
5
4
3
2
1

Here is C++ version of the program:

#include
using namespace std;
int main()
{ static int var=5;
cout <<"\n" << var--;
if (var) main();
cout < system("pause");
}

Answer 4

output: 54321

Answer 5

I concur...
54321