14. A car with a mass of 1,200 kilograms is moving around a circular curve at a uniform velocity of 20 meters per second. The centripetal force on the car is 6,000 newtons. What is the radius of the curve?
A. 160 meters
B. 80 meters
C. 32 meters
D. 16 meters
2007-02-05 17:31:59 · 4 answers · asked by Blaze T 2 in Science & Mathematics ➔ Mathematics
Governing equation: F = mv^2/r
F = 6000 N
m = 1200 kg
v^2 = 20^2 = 400 (m/s)^2
solve for r
r = mv^2/F = 1200*400/6000 = 80 m
2007-02-05 17:35:29 · answer #1 · answered by The Answerer 3 · 0⤊ 0⤋
F = ma
where in this case a is the centripital acceleration
a_cent = v^2/r
6000 = (1200)(20)^2/r
r = 80m
2007-02-05 17:39:41 · answer #2 · answered by Anonymous · 0⤊ 0⤋
x(t) = a million/2gt^2 t = 8 s, g = (about) 9.8 m/s^2 x(8) = 313.6 m (B) This makes some assumptions: a million. The acceleration via gravity (g) is 9.8 m/s^2 (it really varies reckoning on the position you're on earth). 2. there is no air resistance (the stone is falling in a vacuum, in reality, air resistance ought to sluggish the falling of the stone really... notwithstanding it isn't likely that the stone ought to attain terminal speed in only 8 seconds).
2016-11-02 11:10:14 · answer #3 · answered by ? 4 · 0⤊ 0⤋
F = mv^2/r
r = mv^2/F
r = (1,200 kg)(400 m^2/s^2)/6,000 N
r = 80 m
2007-02-05 17:46:30 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋