It is known (only in my head, this a math question) that pygmy flying squirrels normally have a weight distributed with a mean of 40 grams and that the standard deviation from this mean is 3.5g. If 4000 pygmy flying squirrels inhabit one area, how many would weight more than 49grams?
2007-02-05 17:20:10 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I'm not sure, my probability and statistical component is a bit dysfunctional.
Mean = 40
SD = 3.5
P(X>49) = P(X> (49-40)/3.5)
= P(X> 2.571)
P(2.571) = 0.00506(referring to a probability conversion book)
4000 x 0.00506 = 20.24, or 21 squirrels weighing more than 49 grams.
2007-02-05 17:36:53 · answer #1 · answered by sleeplesstwig_89 2 · 0⤊ 0⤋
(49 - 40)/3.5 â 2.571429Ï
1 - Z(2.571429) â 0.005064
4000*0.005064 â 20
2007-02-06 01:39:57 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋