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What are the degree measures of the three angles?

2007-02-05 16:44:45 · 6 answers · asked by kimico 1 in Science & Mathematics Mathematics

6 answers

x + (x + 2) + (x + 4) = 180...x + x + 2 + x + 4 = 180

3x + 6 = 180...3x = 174

x = 58, (x + 2) = 60, (x + 4) = 62

2007-02-05 16:49:44 · answer #1 · answered by jrodbendi 3 · 0 0

the angles are n, n+2 & n+4. They must sum to 180°
n+n+2°+n+4°=180° subtract 6° from each side & combine like terms
3n=174° divide both sides by 3
n=58°
n=2=60°
n+4=62°

the angles are 58°; 60° & 62°

2007-02-06 00:55:28 · answer #2 · answered by yupchagee 7 · 0 0

the sum of all the inside angles of any closed object equals 180 degrees

let 2x be the first angle, then 2x+2 would be the next and 2x+4 the other:

2x + (2x + 2) + (2x + 4) = 180
6x + 6 = 180
6x = 174
x = 29

therefore the angles are:
2(29) = 58 degrees
58 + 2 = 60 degrees
and 58 + 4 = 62 degrees

2007-02-06 00:52:41 · answer #3 · answered by Anonymous · 0 0

let the numbers are x, x+2,x+4 //consecutive even integers
then x+2x+4x = 180 //sum of angles of a triangle
3x+6 = 180
x = (180-6)/3
x=58
the angles are 58,60,62

2007-02-06 00:50:59 · answer #4 · answered by Rhul s 2 · 0 0

If x-2, plus x, plus x+2 = 180 degrees
What is X
3 x = 180
x = 60
x-2 = 58
x+2 = 62

2007-02-06 00:50:52 · answer #5 · answered by a simple man 6 · 0 0

2n - the smallest angle

the sum of the angles is 180

2n + (2n+2) + (2n+4) = 180

solve for n and multiply by 2 to get the smallest one, then add 2 and 4 to get other two

2007-02-06 00:49:49 · answer #6 · answered by Anonymous · 0 0

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