x + (x + 2) + (x + 4) = 180...x + x + 2 + x + 4 = 180
3x + 6 = 180...3x = 174
x = 58, (x + 2) = 60, (x + 4) = 62
2007-02-05 16:49:44
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answer #1
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answered by jrodbendi 3
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the angles are n, n+2 & n+4. They must sum to 180°
n+n+2°+n+4°=180° subtract 6° from each side & combine like terms
3n=174° divide both sides by 3
n=58°
n=2=60°
n+4=62°
the angles are 58°; 60° & 62°
2007-02-06 00:55:28
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answer #2
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answered by yupchagee 7
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the sum of all the inside angles of any closed object equals 180 degrees
let 2x be the first angle, then 2x+2 would be the next and 2x+4 the other:
2x + (2x + 2) + (2x + 4) = 180
6x + 6 = 180
6x = 174
x = 29
therefore the angles are:
2(29) = 58 degrees
58 + 2 = 60 degrees
and 58 + 4 = 62 degrees
2007-02-06 00:52:41
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answer #3
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answered by Anonymous
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let the numbers are x, x+2,x+4 //consecutive even integers
then x+2x+4x = 180 //sum of angles of a triangle
3x+6 = 180
x = (180-6)/3
x=58
the angles are 58,60,62
2007-02-06 00:50:59
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answer #4
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answered by Rhul s 2
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If x-2, plus x, plus x+2 = 180 degrees
What is X
3 x = 180
x = 60
x-2 = 58
x+2 = 62
2007-02-06 00:50:52
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answer #5
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answered by a simple man 6
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2n - the smallest angle
the sum of the angles is 180
2n + (2n+2) + (2n+4) = 180
solve for n and multiply by 2 to get the smallest one, then add 2 and 4 to get other two
2007-02-06 00:49:49
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answer #6
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answered by Anonymous
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