how many ways?

Question

how many ways can 7 students be arranged?
please let me kno how u got the answer thnks

Answer 1

ok here is the answer: Imagine you have 7 chairs and you want to know how many ways you can sit your 7 friends on it ok? so just put 7 lines as if they were chairs: _ _ _ _ _ _ _. Ok so on the first line, you can sit 7 different friends? right? so you place a 7 right there and you'll have something like this: 7 _ _ _ _ _ _. On the second chair, you'll only have 6 different friends to sit, because you've already got one on the first chair, so you place that and you'll get 7 6 _ _ _ _ _. Continue doing that and you'll get something like this: 7 6 5 4 3 2 1. Finally, you multiply all those chances to get your real number of chances, which is: 5040. I hope that helped you!

Answer 2

khg831 and starshine (and others) are *EXACTLY* right, 7! or 7x6x5x4x3x2x1= 5040

This answer is right, that is, UNLESS the students are arranged in a circle. So be careful that they are in a STRAIGHT (or crooked) LINE and this formula will apply. :-)

(if they are in a CIRCLE, they can only be arranged (7-1)! ways, or 6! that is, 6 factorial, or

6x5x4x3x2x1 which = 720)

I found a great website for you that easily explains both... see below! :-)

Hope that helps, Natalie! Good luck!

Answer 3

7! (seven factorial) is correct. By doing the math, you get 5,040 ways. This is because you have seven options for the first slot, then six for the next slot, five for the next, all the way down to just one student.

Answer 4

yes 7! is the correct anwser however if it is a goofy question where X doesnt like to sit by Y then we need those details

Answer 5

7! or (7)(6)(5)(4)(3)(2)(1)

I don't have a calc sorry =)

Answer 6

Not enough information.

What differences define the student to make them differnt. if they are all the samethen they cant be aranged differnently