i need some help factoring this problem completely. its driving me nuts.
y^2 + 8yz + 72y
Thanks.
2007-02-05 16:15:09 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Ok, there is a y common to all terms:
y(y +8z +72). This polynomial can't be factored further,.
2007-02-05 16:17:48 · answer #1 · answered by John T 6 · 1⤊ 0⤋
maybe you're looking for a factorable quadratic of format (y+a)(y+bz). You won;t get it though, since your equation doesn't have a term in z. You can still factor something. So do it. First y
y ( y + 8z + 72).
Then the constant 8
y ( y + 8 (z+9) )
2007-02-06 00:30:32 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
y^2 + 8yz + 72y
y(y+8z+72) is as far as it goes.
2007-02-06 00:41:00 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
just factor out the y from everything, so you get
y(y+8z+72)
2007-02-06 00:18:07 · answer #4 · answered by lori 3 · 0⤊ 0⤋
y^2+8(9y+yz)
2007-02-06 00:43:37 · answer #5 · answered by Andichi 2 · 0⤊ 0⤋